Q:

what is the vertex, axis of symmetry, and the direction of opening for y=2(x+3)^2-5

Accepted Solution

A:
Its vertex is (-3 , -5)Its axis of symmetry is at x = -3The direction of opening of it is upwardStep-by-step explanation:The vertex form of the quadratic function is:y = a(x - h)² + k, where1. The coordinates of its vertex point are (h , k)2. Its axis of symmetry is at x = h3. The direction of opening is upward if a > 0, and downward if a < 0∵ y = 2(x + 3)² - 5∵ y = a(x - h)² + k∴ a = 2 , h = -3 and k = -5∵ The coordinates of the vertex are (h , k)∴ The vertex is (-3 , -5)∵ The axis of symmetry is ta x = h∴ The axis of symmetry is at x = -3∵ a = 2 and 2 > 0∴ The direction of opening is upwardIts vertex is (-3 , -5)Its axis of symmetry is at x = -3The direction of opening of it is upwardLearn more:You can learn more about quadratic function in brainly.com/question/1357167#LearnwithBrainaly